Q10 of 39 Page 207

In the given figure, ABCD is a trapezium in which cm,

cm and cm. find the area of the trapezium.


Given


AD = 16 cm


BC = 40 cm


AC = 41 cm


ABC = 90


Height = AB =?


Here in ABC using Pythagoras theorem


AC2 = AB2 + BC2


412 = AB2 + 402


AB2 = 412 – 402


AB2 = 1681 – 1600 = 81


AB = 9


We know that area of trapezium is × (sum of parallel sides) × height


Therefore Area of trapezium = × (16 + 40) × 9 = 252 cm2.


More from this chapter

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The length of the fence of a trapezium-shaped field ABCD is 130 m and side AB is perpendicular to each of the parallel sides AD and BC. If m, m and m, find the area of the field.

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The parallel sides of a trapezium are 20 cm and 10 cm. Its nonparallel sides are both equal, each being 13 cm. Find the area of the trapezium.

 12

The parallel sides of a trapezium are 25 cm and 11 cm, while its nonparallel sides are 15 cm and 13 cm. find the area of the trapezium.