Subtract:
(i)
from
(ii)
from![]()
(iii)
from
(iv)
from![]()
(v)
from
(vi)
from![]()
(vii)
from
(viii)
from![]()
(i)
Since the denominators of both the numbers are different therefore, we will take their LCM
LCM 0f 3 and 4 = 12
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And,
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Therefore,
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(ii)
Since the denominators of both the numbers are different therefore, we will take their LCM
LCM 0f 6 and 3 = 6
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And,
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Therefore,
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(iii)
Since the denominators of both the numbers are different therefore, we will take their LCM
LCM 0f 9 and 5 = 45
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And,
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Therefore,
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(iv)
We can write, ![]()
Since the denominators of both the numbers are different therefore, we will take their LCM
LCM 0f 1 and 7 =7
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And,
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Therefore,
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(v)
We can write, ![]()
Since the denominators of both the numbers are different therefore, we will take their LCM
LCM 0f 1 and 11 = 11
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And,
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Therefore,
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(vi)
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(vii)
Since the denominators of both the numbers are different therefore, we will take their LCM
LCM 0f 13 and 5 = 65
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And,
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Therefore,
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(viii)
We can write, ![]()
Since the denominators of both the numbers are different therefore, we will take their LCM
LCM 0f 1 and 7 = 7
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And,
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Therefore,
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(ii)
(iii)
(v)
(vii)
(viii)
(x)




find the other.