Using the rearrangement property find the sum:
(i)
(ii)
(iii)
(iv)
Rearrangement property says that, the numbers in an addition expression may be arranged and grouped in any order.
Therefore,
(i)![]()
We arrange the numbers with same denominators together,
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Now, we take LCM of 3 and 5=15
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And,
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Therefore,
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(ii)
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We arrange the numbers,
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LCM of 3 and 6 =6
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And,
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LCM of 4 and 8 =8
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And,
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Now,
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Now, we take LCM of 6 and 8=24
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And,
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Therefore,
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In lowest terms,
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(iii)
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We arrange the numbers,
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LCM of 20 and 10 =20
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And,
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LCM of 14 and 7 =14
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And,
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Now,
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Now, we take LCM of 20 and 14=140
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And,
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Therefore,
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(iv)
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We arrange the numbers,
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LCM of 4 and 9 =18
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And,
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Now,
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In lowest terms,
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Now, we take LCM of 1 and 18=18
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And,
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Therefore,
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Couldn't generate an explanation.
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(ii)
(iii)
(v)
(vii)
(viii)
(x)
from
(ii)
from
from
(iv)
from
from
from
from
(viii)
find the other.
If one of the numbers is
find the other.