Q14 of 120 Page 89

sin (450+θ) - cos (450-θ) is equal to

As we know that, sin(90°-θ) = cos θ by sine property.

So, sin(45°+θ)-cos(45°-θ) = sin[90°-(45°-θ)]-cos(45°-θ)


= cos(45°-θ)-cos(45°-θ) (By using identity)


= 0

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