Q7 of 120 Page 95

tan θ +tan (900- θ) = sec θ sec (900- θ)

L.H.S: tan θ + tan (90° - θ)

= tan θ + cot θ


[∵tan (90° - θ) = cot θ]







= sec θ cosec θ


= sec θ sec (90° - θ) [∵cosec θ = sec (90° - θ)]


: R.H.S


Hence, proved.


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