Q7 of 70 Page 280

Find the points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis.

Given equation, 3x + 4y = 12


⇒ 4y = 12 – 3x



When x = – 4, then,







⇒ y = 6


When x = 0, then,






⇒ y = 3


When x = 4, then,






⇒ y = 0


Thus we have the following table,
















X



– 4



0



4



Y



6



3



0



On plotting the points, ( – 4, 6), (0, 3) and (4, 0) we get the following graph,



Clearly from the graph, it cuts x axis at (4, 0) and y axis at (0, 3)


More from this chapter

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5

For what value of k does the point (k, – 3) lies on the line 3x – y = 6?

 6

If x = 3, y = – 2 satisfies 2x – 3y = k, then find the value of k.

 8

The area of the triangle formed by the line x + 3y = 12 and the coordinate axes is

 9

The question consists of two statements, namely, Assertion (A) and Reason (R). Choose the correct option.











Assertion (A)



Reason (R)



Y = mx represents a line passing through the origin.



Any line parallel to x-axis is y = k.