Now, 
We know that a determinant of a 3 x 3 matrix is calculated as
= 0 – 1[0 – (-3)(-2)] + 2[(-1)(3) – 0]
= 0 – 1[0 - 6] + 2[-3 – 0]
= 0 – 1[-6] + 2[-3]
= 0 + 6 – 6
= 0
The determinant of the above matrix is 0.
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