If A is an invertible matrix of order 2, then det (A–1) is equal to


{since adj(A) is of order n and |Adj(A)| = |A|n-1}
Alternative-
We know that AA-1 = I
So |A||A-1| = |I| = 1

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![a = [ ccc 2&-1&1 -1&2&-1 1&-1&2 ]](https://static.philoid.co/ncertusercontent/solutions/?domain=gF&l=PROJ28781/1554209812139147.png)