Express the following recurring decimals into vulgar fractions :
(a)
= 0.666…. .........(1)
10 ×
= 6.666… ........ (2)
(2) - (1) 𡴩 ×
= 6
∴
= 6/9 = 2/3
(b)
= 0.161616….. ---(1)
100 ×
= 16.1616….. -----(2)
Subtracting (1) from (2) , we get
99 ´
= 16
∴
= 16/99
(c) 0.
= 0.234234….. ----(i)
1000 × 0.
= 234.234234… -----(ii)
Subtracting (i) from (ii) , we get
999 × 0.
= 234
∴ 0.
= 234/999.
(d)
= 0.125454…. -----(i)
∴ 100 ×
= 12.545454…. -----(ii)
And, 10000 ´
= 1254.5454… -----(iii)
Subtracting (ii) from (iii) , we get
9900 ×
= 1242
∴
= 1242/9900 = 69/550.
10 ×
(2) - (1) 𡴩 ×
∴
(b)
100 ×
Subtracting (1) from (2) , we get
99 ´
∴
(c) 0.
1000 × 0.
Subtracting (i) from (ii) , we get
999 × 0.
∴ 0.
(d)
∴ 100 ×
And, 10000 ´
Subtracting (ii) from (iii) , we get
9900 ×
∴
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