Rationalize the denominator of
(i)
(ii)
(iii)
(i) The denominator is a trinomial surd.
We proceed as with a binomial surd by grouping two of the terms. Thus,

= 9 + 6 √5 + 5 - 8
= 6 + 6 √5
= 6(1+ √5)
\\


=
=
=
(ii) The denominator is a trinomial surd.
We proceed as with a binomial surd by grouping two of the terms.
Thus,
= 3 –


=
(iii) The denominator is a trinomial surd.
We proceed as with a trinomial surd, by grouping two of the terms.
Thus,

We proceed as with a binomial surd by grouping two of the terms. Thus,

= 9 + 6 √5 + 5 - 8
= 6 + 6 √5
= 6(1+ √5)
\\


=
=
=
(ii) The denominator is a trinomial surd.
We proceed as with a binomial surd by grouping two of the terms.
Thus,
= 3 –


=
(iii) The denominator is a trinomial surd.
We proceed as with a trinomial surd, by grouping two of the terms.
Thus,

AI is thinking…
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
(ii)
(iii)
(ii)
(approx.).