Examine, whether the following numbers are rational or irrational:
(i)
(ii) 5-√2
(i)
We have,

= 2 + 2√6 + 3
= 5 + 2![]()
The sum of a rational number and an irrational number is irrational number. Therefore, it is an irrational number.
(ii) 5-√2
Now √2,
Consider,

Where p and q are the integers having no common factor and q≠0.
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So p2 is an even integer.
⇒ p is an even integer.
Let p = 2m
So p2 = 4m2
⇒ 2q2 = 4m2
⇒ q2 = 2m2
q2 is an even integer.
So, q is an even integer.
Since both p and q have common factor 2 and are even. This contradicts the assumption that p and q have no common factor.
Hence √2 is irrational number.
The difference of a rational number and an irrational number is an irrational number.
Therefore, 5 -
is an irrational number.
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