Prove that √3 + √5 is an irrational number.
Prove that √3 + √5 is an irrational number.
Let √3 + √5 be a rational number, say r
Then √3 + √5 = r
On squaring both sides,
(√3 + √5)2 = r 2
3 + 2√15 + 5 = r 2
8 + 2√15 = r 2
2√15 = r 2 - 8
√15 = ( r 2 - 8)/2
Now ( r 2 - 8)/2 is a rational number and √ 15 is an irrational number.
Since a rational number cannot be equal to an irrational number. Our assumption that
√3 + √5 is rational is wrong.
Then √3 + √5 = r
On squaring both sides,
(√3 + √5)2 = r 2
3 + 2√15 + 5 = r 2
8 + 2√15 = r 2
2√15 = r 2 - 8
√15 = ( r 2 - 8)/2
Now ( r 2 - 8)/2 is a rational number and √ 15 is an irrational number.
Since a rational number cannot be equal to an irrational number. Our assumption that
√3 + √5 is rational is wrong.
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