Q29 of 72 Page 12

In the given circuit, calculate the current shown by the ammeter and total resistance of the circuit.

In the circuit, two resistances of 2 Ω each are connected in series and then connected to 4Ω in parallel. The equivalent resistance of resistances in series = 2+2 = 4Ω . The equivalent resistance of 4Ω and the resultant of two 2 ohms (4Ω ) = + = + = = or R = 2 ohms. As total equivalent resistance is 2 ohms, Current in circuit will be = = 2 amperes. The ammeter will show a current of 2 amps, and the total resistance of the circuit is 2 ohms.

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27 How much current will an electric heater draw from a 220 volt line if the resistance of the heater is 44 ohms? 28 Potential difference across the end of a wire is 0.6V which carries a current of 8 amperes. Find the resistance of the wire. 30 An electric bulb of 40W is connected to a source of 2 20v. What will be the current drawn and the resistance of the bulb? 31 Read the following statements. Write true or false against each:
(i)   The quantity of charge flowing past a point multiplied by the time gives the current.
(ii)  The flow of charge through a conducting wire, connected to a cell, is due to the chemical reaction inside the cell.
(iii) The resistivity of all pure metals increases with rise in temperature.
(iv) Ohm's law is a relation between the power used, the current and the potential difference in a circuit.
(v)  A series circuit has only one conducting path for the electrons that move through it; a parallel circuit has multiple conducting paths.
(vi) A conducting wire offers resistance to the flow of electrons because electrons repel each other in the wire.