A copper wire has a diameter of 0.5 mm and resistivity of 1.6 ohm cm. How much of this wire would be required to make a 10 ohm coil?
Diameter of copper wire, D = 0.5mm Therefore Area of cross section A =
= 0.1963 mm2 Resistivity of the copper wire ρ = 1.6 ohm cm = 16 ohm mm Let the required length be l Then l = R × 
=10 ×
= 0.12269 mm
= 122. 7 × 10-6 m
=10 ×
= 0.12269 mm
= 122. 7 × 10-6 m
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