A piece of wire is redrawn by pulling it until its length is doubled. Compare the new resistance with the original value?
Let the original dimensions of the wire be of length l, area of cross section A and resistivity ρ .
Therefore resistance R =
Since the total volume of the cylindrical wire is constant, the length of the wire is doubled by pulling it and hence the cross sectional area of the wire is halved.
Therefore the new resistance R′ =
= 4R
Thus the resistance is 4 times its original value.
Therefore resistance R =
Since the total volume of the cylindrical wire is constant, the length of the wire is doubled by pulling it and hence the cross sectional area of the wire is halved.
Therefore the new resistance R′ =
Thus the resistance is 4 times its original value.
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