The bisector of interior angle A of a triangle AB meets BC in D and the bisector of exterior angle A meets BC produced in E. Prove that 
Given: ΔABC, AD bisects interior ∠A and AE bisects exterior ∠A meeting BC at D and BC produced at E.
To prove:
Proof: In ΔABC, AD bisects interior ∠A
∴
(Angle Bisector theorem)…………………(1)
Similarly in DABC, AE bisects exterior ∠A
∴
………………..(2)
From equation (1) and (2),
Hence Proved.
To prove:
Proof: In ΔABC, AD bisects interior ∠A
∴
Similarly in DABC, AE bisects exterior ∠A
∴
From equation (1) and (2),
Hence Proved.
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