The foot of a ladder is 6 m away from a wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its tip reach?
Given: AB = 8 m
CD = 6 m
To find: Height to the tip reaches
Theorem Used:
Pythagoras theorem:
In a right-angled triangle, the squares of the hypotenuse is equal to the sum of the squares of the other two sides.
Explanation:

Let length of ladder be AD = BE = t m
In
ACD
AD2=AC2+CD2
t2= 82+62 ……. (i)
In
BCE
BE2=BC2+EC2
t2= BC2+82 …… (ii)
From (i) and (ii)
BC2+82=82+62
BC2=62
BC=6m
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