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6. Triangles
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Q21 of 56 Page 6

In a Δ ABC, AD is the bisector of ∠A, meeting side BC at D. If AC = 4.2 cm, DC = 6 cm, BC = 10 cm,  find AB.

 

Given: In a Δ ABC, AD is the bisector of  ∠ A, meeting side BC at D. AC = 4.2 cm, DC = 6 cm and BC = 10 cm.
To find: AB. 
In Δ ABC,
[By internal bisector theorem]
AB = 4 × 4.2/6 = 2.8 cm
∴ AB = 2.8 cm  

More from this chapter

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19 In fig. DE || BC. If AD = x, DB = x – 2, AE = x + 2 and EC = x – 1, find the value x.                         
         
20 In a Δ ABC, D and E are points on the sides AB and AC respectively such that DE || BC. If AD = 4 cm, AE = 8 cm, DB = x – 4
and EC = 3x – 19, find x.
22 In Δ ABC, ∠ B = 90° and D is the mid-point of BC. Prove that AC2 = AD2 + 3CD2.
23 ABC is a triangle in which AB = AC and D is a point on the side AC such that BC2 = AC × CD. Prove that BD = BC.
Questions · 56
6. Triangles
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