Q30 of 56 Page 6

 In fig,  ∠ B < 90° and segment AD ^ BC, show that b2 = h2 + a2 + x2 - 2ax
 

Given: In ΔABC, ∠ B < 90° and segment AD ⊥ BC.
To prove: b2 = h2 + a2 + x2 – 2ax
Proof:
b2 = h2 + (a - x)2
b2 = h2 + a2 + x2 - 2ax.

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