Q7 of 51 Page 6

Solve 3(x-1) ≤ 2(x-3)


3(x-1) ≤ 2(x-3)

⇒ 3x - 3 ≤ 2x – 6

⇒ 3x – 3 + 3 ≤ 2x – 6 + 3 (Rule 1)

⇒ 3x ≤ 2x – 3

⇒ 3x – 2x ≤ 2x –2x - 3 (Rule 1)

⇒ x ≤ -3

Solution set = (-∞ , 3).

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