Solve the following inequalities graphically in two-dimensional plane-3x + 2y > -6.

-3x + 2y = -6. ...(i)

Putting x = 0, y = -3, therefore the point on the v-axis is (0, -3)

The point on the x-axis is (2,0). AB is the graph of(i).

Putting x - 0, y = 0 in the given inequality, we have -3(0) + 2 (0) > -6 or 0 > -6 or 0 < 6, which is true.

Hence, origin lies in the half plane region I. Clearly any point on the line satisfy the given inequality.

Hence, the shaded region I including the points on line is the solution region of the inequality.