Solve

Multiplying both sides by 60 i. e., L. C. M. of 3, 4 and 5 we have

⇒

⇒ 15x < 20(5x - 2) – 12(7x – 3)

⇒ 15x < 100x – 40 – 84x + 36

⇒ 15x < 16x - 4

⇒ 15x + 4 < 16x – 4 + 4 (Rule 1)

⇒ 15x + 4 < 16x

⇒ 15x – 15x + 4 < 16x – 15x

⇒ 4 < x

⇒ x > 4

Solution set = (4, ∞ ).