If the equation x2 – bx + 1 = 0 does not possess real roots, then

If the equation does not possess real roots thend = b2 – 4ac 0Here a = 1, b = – b, c = 1d = b2 – 4 < 0b2 < 4b < 2– 2 < b < 2

Q11 of 242 Page 9

If the equation x² – bx + 1 = 0 does not possess real roots, then

If the equation does not possess real roots then

d = b² – 4ac 0

Here a = 1, b = – b, c = 1

d = b² – 4 < 0

b² < 4

b < 2

– 2 < b < 2

If the equation (a² + b²) x² – 2 (ac + bd) x + c² + d² = 0 has equal roots, then

If the roots of the equation (a² b²) x² – 2b (a + c) x + (b² + c²) = 0 are equal, then

If x = 1 is a common root of the equations ax² + ax + 3 = 0 and x² + x + b = 0, then ab =

If p and q are the roots of the equation x² + px + q = 0, then