If y = 1 is a common root of the equations ay2 + ay + 3 = 0 and y2 + y + b = 0, then ab equals
If y = 1 is root of both the equation it will staify both the equations
Putting y = 1 in first equation
ay2 + ay + 3 = 0
2a + 3 = 0
a = ![]()
Putting value of y in second equation
2 + b = 0
B = – 2
Now ab =
x – 2
ab = 3
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