The rate constant for a first order reaction is 60 s-1. How much time will it take to reduce 1g of the reactant to 0.0625 g?
Given: Rate constant (k) = 60 s-1
Mass of reactant at intial time (R0) = 1g
Mass of reactant after time t (R)= 0.0625g
We apply the formula:
t =
log ![]()
⇒ t =
log ![]()
⇒ t = 0.0462 s
Thus, the time to reduce 1g of the reactant to 0.0625 g is 0.0462s
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