Q29 of 109 Page 3

For what value of k, – 4 is a zero of the polynomial x2 – x – (2k + 2)?

Given,


A polynomial x2 – x – (2k + 2)


– 4 is a zero of the given polynomial


As – 4 is the zero


So we get,


x2 – x – (2k + 2) = 0


( – 4)2 – ( – 4) – (2k + 2) = 0


16 + 4 – (2k + 2) = 0


20 – (2k + 2) = 0


– (2k + 2) = – 20


2k + 2 = 20


And


2k = 18


k = 18/9 = 2


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