If α and β are the zeros of the polynomial f(x) = x2 + px + q, then a polynomial having and is its zeros is

Given,f(x) = x2 + px + qα + β = – pαβ = q1/α + 1/β = – p/qx2 + p/q x + 1/qSo here we get,g(x) = qx2 + px + 1

Q5 of 109 Page 3

If α and β are the zeros of the polynomial f(x) = x² + px + q, then a polynomial having and is its zeros is

Given,

f(x) = x² + px + q

α + β = – p

αβ = q

1/α + 1/β = – p/q

x² + p/q x + 1/q

So here we get,

g(x) = qx² + px + 1

If one zero of the polynomial f (x) = (k² + 4) x² + 13x + 4k is reciprocal of the other, then k =

If the sum of the zeros of the polynomial f(x) = 2x³ – 3kx² + 4x – 5 is 6, then the value of k is

If α, β are the zeros of polynomial f(x) = x² – p (x + 1) – c, then (α + 1) (β + 1) =

If α, β are the zeros of the polynomial f(x) = x² – p (x + 1) – c such that (α + 1) (β + 1) = 0, then c =