Q2 of 25 Page 86

Write five solutions of the equation x + y = 7.

(a)


Let x = 1,


As, x + y = 7


⇒ 1 + y = 7


⇒ y = 6


Hence, solution is x = 1 and y = 6.


(b)


Let x = 2,


As, x + y = 7


⇒ 2 + y = 7


⇒ y = 5


Hence, solution is x = 2 and y = 5.


(c)


Let x = 3,


As, x + y = 7


⇒ 3 + y = 7


⇒ y = 4


Hence, solution is x = 3 and y = 4.


(d)


Let x = 4,


As, x + y = 7


⇒ 4 + y = 7


⇒ y = 3


Hence, solution is x = 4 and y = 3.


(e)


Let x = 5,


As, x + y = 7


⇒ 5 + y = 7


⇒ y = 2


Hence, solution is x = 5 and y = 2.


More from this chapter

All 25 →
1

By using variables x and y form any five linear equations in two variables.

 3

Solve the following sets of simultaneous equations.

i. x + y = 4; 2x - 5y = 1


ii. 2x + y =5; 3x – y =5


iii. 3x – 5y =16; x - 3y = 8


iv. 2y – x =0; 10x + 15y =105


v. 2x +3y + 4 = 0; x – 5y = 11


vi. 2x – 7y =7; 3x + y =22

 1

In an envelope there are some 5 rupee notes and some 10 rupee notes. Total amount of these notes together is 350 rupees. Number of 5 rupee notes are less by 10 than number of 10 rupee notes. Then find the number of 5 rupee and 10 rupee notes.

 2

The denominator of a fraction is 1 more than twice its numerator. If 1 is added to numerator and denominator respectively, the ratio of numerator to denominator is
1 : 2. Find the fraction.