Q4 of 25 Page 90

The total number of lions and peacocks in a certain zoo is 50. The total number of their legs is 140. Then find the number of lions and peacocks in the zoo.

Let the number of lions be 'x' and peacocks be 'y'


Given, Total no of lions and peacocks is 50


⇒ x + y = 50


⇒ x = 50 - y eq.[1]


Also, Total no of their legs is 140, as lion has four legs and peacocks has 2 legs


⇒ 4x + 2y = 140


⇒ 4(50 - y) + 2y = 140


⇒ 200 - 4y + 2y = 140


⇒ 2y = 60


⇒ y = 30


Using this in eq.[1]


⇒ x = 50 - 30 = 20


Therefore,


No of lions, x = 20


No of peacocks, y = 30


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