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8. Quadrilaterals
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Q13 of 56 Page 82

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.


Let ABCD is a parallelogram.


Since, DC||AB and DA is transversal.


∠A + ∠D = 180


∠A + ∠D = 90


∠PAD + ∠PDA = 90


∠APD = 90


∠SPQ = 90


Similarly, ∠PQR = 90, ∠QRS = 90


And ∠PSR = 90


Thus, PQRS is a quadrilateral each of whose angles is 90.


Hence, PQRS is a rectangle.


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11

Show that the quadrilateral formed by joining the mid-points of the consecutive sides of a square is also a square.

12

E and F are respectively the mid-points of the non-parallel sides AD and BC of a trapezium ABCD. Prove that EF || AB and EF = (AB + CD).

[Hint: Join BE and produce it to meet CD produced at G.]

14

P and Q are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. Show that PQ is bisected at O.

15

ABCD is a rectangle in which diagonal BD bisects ∠B. Show that ABCD is a square.

Questions · 56
8. Quadrilaterals
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