Attempt any two subquestions form the following:
If the second term and the fourth terms of an A.P. are 12 and 20 respectively, then find the sum of first 25 terms:
Given: a2 = 12 and a4 = 20.
Let first term is a and common difference is d, second term is a + d, third term is a + 2d and so on
Then a2 = a + d = 12 ….(1)
And a4 = a + 3d = 20 ….(2)
Now, on subtracting eq (1) from eq(2),
a + 3d – a- d = 20 - 12
⇒ 2d = 8
⇒ d = 4
⇒ a = 12-4 = 8
Hence, sum of the n terms is given as:
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⇒ S25 = 1400
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