Q4 of 23 Page 1

Attempt any two subquestions form the following:

Solve the following simultaneous equations:


Given:

let


hence, the equation will be:


27a + 31b = 85 …(1)


31a + 27b = 89 … (2)


Multiplying equ. (1) by 31 and (2) by 27.


⇒ 837a + 961b = 2635 …(3)


837a + 729b = 2403 … (4)


Subtract (4) from (3)


⇒ 232b = 232


⇒ b = 1


Put value b in (1)


⇒ 27a + 31(1) = 85


⇒ 27a = 85 – 31


⇒ 27a = 54


⇒ a = 2


Now,


⇒ x = 5/2 and y = -2


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