Q1 of 23 Page 1

Solve sub-questions:

In the following figure, RP: PK = 3:2, find the value of A(ΔTRP) : A(ΔTPK).


Construction: Extend PK and drop a perpendicular to that extended line.



The bases RP and PK are on the same line and vertex T is common.


Triangles have the same height. Considering


If Given RP:PK = 3:2


Let RP=3x and PK= 2x


[Ratio of their areas = the ratio of their altitudes]



More from this chapter

All 23 →