Q2 of 23 Page 1

Solve sub-questions:

In the following figure, seg AB is a diameter of the circle, m (arc AKC) = 40° . Find the value of m (arc BMC).


Seg AB is a diameter

⇒ M (arc ACB) =180° [Angle Made in Semi circle = 180°]


⇒ M (arc AKC) +m (arc BMC) = m (arc ACB) [Arc Addition


Property]


⇒ 40+ m (arc BMC) = 180°


⇒ M (arc BMC) = 180° -40°


⇒ M (arc BMC) =140°


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