Solve sub-questions:
Show that ABCD is a parallelogram if A = (4, 8), B = (5, 5), C = (2, 4), D = (1, 7)
Given: A = (4, 8), B = (5, 5), C = (2, 4), D = (1, 7)
To Prove: AD||BC
AB||DC

Proof:
Let A (4,8) = (x1, y1); B (5,5) = (x2, y2);
C (2,4) = (x3, y3) and D (1,7) = (x4, y4)
Distance between two points P (x1, y1) and Q (x2, y2) = ![]()
The slope of the line AB =
[Distance formula]
=![]()
=
…(i)
The slope of the line DC =
[Distance formula]
=![]()
=
…(ii)
The slope of the line AD =
[Distance formula]
=![]()
=
…(iii)
The slope of the line BC =
[Distance formula]
=![]()
The slope of line AB = The slope od’s the line DC [From (1) and (2)]
∴ AB||DC
The slope of line AD = The slope of the line BC [From(3) and (4)]
∴ AD||BC
Hence, ABCD is a parallelogram.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
