Solve sub-questions:
A person standing on the bank of a river observes that the angle of elevation of the top of a tree standing on the opposite bank is 60°. When he moves 40 m away from the bank, he finds the angle of elevation to be 30°. Find the height of the tree and width of the river. ![]()
Let BC be height of the tree.
AB be the breadth of the river.
A be the initial position of the person
D be the final position of the person
∠CAB = 60° & ∠CDB = 30° & DA = 40m
Let AB = x & BC = h

In Δ DBC
⇒ ![]()
⇒ ![]()
⇒
……. (1)
In Δ ABC
⇒ ![]()
⇒![]()
⇒
…… (2)
Using (1) & (2)
![]()
⇒ ![]()
⇒ ![]()
⇒![]()
⇒![]()
⇒ AB = 20m
⇒ BC =20√3 m =20×1.73 =34.6m
∴Height of the tree is 34.6m and width of the river is 20m.
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