Solve Question:
Two buildings are in front of each other on either side of a road of width 10 meters. From the top of the first building which is 20 meters high, the angle of elevation to the top of the second is 45owhat is the height of the second building?

We have to find the height of 2nd building is which is 1st building + ED
We know that Tanθ = ![]()
From, triangle CED we can write Tan 45° = ![]()
1 = ![]()
ED = 10 cm.
∴ Height 2nd building is 1st building + ED
Height 2nd building = 20 + 10 = 30 cm.
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