Solve Question:
Write down the equation of a line whose slope is 3/2 and which passes through point P, where P divides the line segment AB joining A (-2, 6) and (3, -4) in the ratio 2:3.
Let P (x, y) be the point that divides the line segment in the ratio 2:3
A (-2, 6) ≡ (x1, y1)
B (3, -4) ≡ (x2, y2)
2:3 ≡ m:n
p (x, y) = ![]()
=
, ![]()
= (0,2)
Now we are given with slope 3/2 to find the equation.
Equation = (y-y1) = m(x-x1)
y-2 =
(x-0)
3x-2y + 4 = 0
Couldn't generate an explanation.
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