Q2 of 23 Page 1

Attempt of the following question:

Solve the following quadratic equation by Factorisation method:
x2 + 7x + 10 = 0.

We have x2 + 7x + 10 = 0


Here, a (coefficient of x2) = 1


b (coefficient of x) = 7


c (constant term) = 10


To factorize this equation, we have to find numbers p and q such that p + q = b and pq = c


i.e. pq = 10


the possible values for p & q are 2 & 5. Because (2 × 5 = 10) and (2 + 5 = 7)


X2 + 5x + 2x + 10 = 0


∴ x(x + 5) + 2(x + 5) = 0


∴ (x + 5)(x + 2) = 0


∴ x = -5 or x = -2


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