Attempt of the following question:
Find the sum of all numbers from 50 to 350 which are divisible by 6. Hence find the 15th term of that A.P.
Starting from 50 the first number divisible by 6 is 54, this series will go forward as 60, 66 and so on
⇒ And moving back from 350 the last number will be 348
We know
tn = a + (n-1)d
348 = 54 + (n-1)6
348-54 = 6n-6
6n = 300
n = 50
t15 = 54 + (15-1)6
t15 = 138
Couldn't generate an explanation.
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