Attempt of the following question:
There are three boys and two girls. A committee of two is to be formed.
Find the probability of the following events:
Event A : The committee contains at least one girl.
Event B : The committee contains one boy and one girl.
Let the tree boys be B1, B2 and B3
And, the two girls are: G1 and G2
Sample Space
⇒ S = {B1B2, B1B3, B1G1, B1G2, B2B3, B2G1, B2G2, B3G1, B3G2, G1G2}
⇒ n(S) = 10
Event A = The committee contains at least one girl.
⇒ A = {B1G1, B1G2, B2G1, B2G2, B3G1, B3G2, G1G2}
⇒ n(A) = 7
![]()
Event B: The committee contains one boy and one girl.
⇒ B = {B1G1, B1G2, B2G1, B2G2, B3G1, B3G2, }
⇒ n(B) = 6
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


