Find the co-ordinates of the points of trisection of the line segment AB with A(2, 7) and B(-4, -8).
let The points of trisection of a given line AB be P and Q
Then the ratio AP:PQ:QB = 1:1:1
Hence we get AP:PB = 1:2
And AQ:QB = 2:1
A point P(x,y) divides the line formed by points (a,b) and (c,d) in the ratio of m:n, then the coordinates of the point P is given by
and ![]()
To find point P(x,y)
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x = 0
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y = 2
To find the point Q(x',y')
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x' = -2
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y' = -3
Hence point P = (0,2) and Q = (-2,-3)
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