Find the coordinates of the circumcentre of a triangle whose vertices are (-3,1),(0,-2) and (1,3)
The circumcentre is equidistant from all the points of the triangle.
Let the coordinates of circumcentre be (x,y)
=
...i
And
...ii
Squaring and simplifying i , we get
2x-2y = -6
Squaring and simplifying ii , we get
2x + 10y = 6
Solving the above equations, we get
x = ![]()
y = ![]()
hence the coordinates of circumcircle is (
)
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