Find the coordinates of the centre of the circle passing through the points P(6,-6), Q(3,-7)and R(3,3).
According to the distance formula, the distance 'd' between two points (a,b) and (c,d) is given by
.....(1)
Let the centre be A(x,y)
As it passes through the given points, distance between centre and the points is the radius.
AP = ![]()
AQ = ![]()
AR = ![]()
As AP = AQ
Squaring both sides
(x-6)2 + (y + 6)2 = (x-3)2 + (y + 7)2
Simplifying
12y-12x + 72 = 14y-6x + 58
2y + 6x-14 = 0... (a)
AP = AR
Squaring both sides and simplifying
6y-6x + 54 = 0 ...(b)
Solving for x and y using (a) and (b)
We get x = 3; y = -2
Hence centre is (3,-2)
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