A storm broke a tree and the treetop rested 20 m from the base of the tree, making an angle of 60° with the horizontal. Find the height of the tree.

Let AB be a tree, and C is the point of break.
Height of tree = BC + AC
As, the treetop is rested 20 m from the base, making an angle of 60° with the horizontal.
In ∆ABC
AB = 20 m
∠ABC, θ = 60°
Now,
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⇒ AC = 20 tan 60°
⇒ AC = 20√3 m
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⇒ BC = 40 m
Height of tree = BC + AC = (40 + 20√3) meters.
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