Q5 of 45 Page 138

Prove the following.

(secθ + tanθ) (1 - sinθ) = cosθ

Taking LHS


(1 - sinθ) (secθ + tanθ)




[(a + b)(a - b) = a2 - b2]


[ sin2θ + cos2θ = 1]


= cos θ


= RHS


Proved !


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