Prove that the following are irrational.
![]()
6 + √2
Let 6 + √2 be a rational number equal to
, where a,b are positive co-primes. Then,
6 + √2 = ![]()
⇒ √2![]()
⇒ ![]()
Since a and b are integers,
is also rational and hence, √2
should be rational. This is contracdicts the fact that√2
is irrational. Therefore , our assumption is false and hence, 6 + √2 is irrational.
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