Q7 of 54 Page 22

If (2.3) x = (0.23) y = 1000 then find the value of

2.3x = 0.23y = 1000

Consider 2.3x = 1000


⇒ log 2.3x = log103


⇒ x log2.3 = 3 log 10


⇒ log2.3 = [∵ log10 = 1] …..I


Consider 0.23y = 1000


⇒ log 0.23y = log 1000


⇒ y log0.23 = log 103


⇒ y log 0.23 = 3 log 10


⇒ log 0.23 = ……..II


Subtract eq. II from I


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