Prove that
is irrational, where p, q are primes.
Let √p + √q
be rational
⇒ √p + √q
[where a, b are co-primes and integers]
Squaring both sides
⇒ ![]()
⇒ ![]()
⇒ 2√pq = a^2/b^2 -p-q
⇒ ![]()
⇒
….I
∴ from Eq. I our assumption contradicts here, because p is rational
Hence, √p + √q is irrational number.
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