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5. Quadratic Equations
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Q12 of 58 Page 118

A ball is thrown vertically upward from the top of a building 96m tall with an initial velocity 80m/second. The distances of the ball from the ground after t seconds is s = 96 + 80t - 4.9t2. After how may seconds does the ball strike the ground.

s = 96 + 80t - 4.9t2

When the ball reaches the ground, s = 0


4.9t2 - 80t - 96 = 0






Since time cannot be negative so negative root is neglected


⇒ Time taken = 17.44 s


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Questions · 58
5. Quadratic Equations
1 1 1 1 1 1 1 1 2 2 2 2 1 1 1 1 1 1 1 1 1 2 3 4 5 6 7 8 9 10 1 1 1 1 2 2 2 2 3 3 4 5 6 7 8 9 10 11 12 13 1 1 1 2 2 3 4 5
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